3x^2-7=2(x^2+3)

Solution for 3x^2-7=2(x^2+3) equation:

Simplifying
3x2 + -7 = 2(x2 + 3)

Reorder the terms:
-7 + 3x2 = 2(x2 + 3)

Reorder the terms:
-7 + 3x2 = 2(3 + x2)
-7 + 3x2 = (3 * 2 + x2 * 2)
-7 + 3x2 = (6 + 2x2)

Solving
-7 + 3x2 = 6 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-7 + 3x2 + -2x2 = 6 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-7 + 1x2 = 6 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-7 + 1x2 = 6 + 0
-7 + 1x2 = 6

Add '7' to each side of the equation.
-7 + 7 + 1x2 = 6 + 7

Combine like terms: -7 + 7 = 0
0 + 1x2 = 6 + 7
1x2 = 6 + 7

Combine like terms: 6 + 7 = 13
1x2 = 13

Divide each side by '1'.
x2 = 13

Simplifying
x2 = 13

Take the square root of each side:
x = {-3.605551275, 3.605551275}